Crossword helper: Difference between revisions
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(Created page with "== bash == awk 'length==6' /usr/share/dict/american-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t" Find all words in the American English dictionary with a length of 6 charach...") |
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== bash == | == bash == | ||
awk 'length==6' /usr/share/dict/british-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t" | |||
awk 'length==6' /usr/share/dict/american-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t" | awk 'length==6' /usr/share/dict/american-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t" | ||
Find all words in the American English dictionary with a length of 6 charachter that start with either a lower or upper case character, an "a" in the second position, three lower case characters and a "t" at the end. I'm quite sure the regular expression could be optimized (the redundant [a-z] bothers me). | Find all words in the American English dictionary with a length of 6 charachter that start with either a lower or upper case character, an "a" in the second position, three lower case characters and a "t" at the end. I'm quite sure the regular expression could be optimized (the redundant [a-z] bothers me). | ||
Latest revision as of 12:52, 24 February 2021
bash
awk 'length==6' /usr/share/dict/british-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t"
awk 'length==6' /usr/share/dict/american-english | grep "^[a-zA-Z]a[a-z][a-z][a-z]t"
Find all words in the American English dictionary with a length of 6 charachter that start with either a lower or upper case character, an "a" in the second position, three lower case characters and a "t" at the end. I'm quite sure the regular expression could be optimized (the redundant [a-z] bothers me).